3 Description. The SNx4HC08 devices contain four independent. 2-input AND gates. They perform the Boolean function Y = A ○ B or Y = A + B in positive logic. 74HC08 Datasheet, 74HC08 Quad 2-input AND Gate Datasheet, buy 74HC 74HC08D from NEXPERIA >> Specification: AND Gate, 74HC08, 2 Input, mA, 2 V to 6 V, SOIC
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It is important to give the correct part numbers! Get the pinout correct. Negative to resistor, resistor to GND. Whiskeyjack 3, 2 16 Seems like you got an arduino.
74HC08 AND Gate Example Circuit | Sully Station Technologies
Connect an LED to pin 1 and pin 2 each along with current limiting resistors. Now remove the wire and connect pin1 to GND this time. Positive of LED to pin 2. Home Questions Tags Users Unanswered. Here is the pinout diagram:. Then shouldn’t the diagram I drew above work? Negative to the GND via a resistor.
And TTL outputs are much better at sinking current rather than sourcing it, so don’t try to drive 74h08 LED output to ground. Here is the pinout diagram: I have the above IC and I want to check them before using them. Sign up using Facebook. This verifies a working gate.
But keep the switch and LED connections as they are. What 74hc088 I do to test them? If your parts are reallyand with no letters other than possibly L or LS in the middle, like 74LS04 they are bipolar TTL logic, and require a 5 volt power supply for correct operation.
Peter Bennett 36k 1 28 The 74HC parts can use a power supply between 2 volts and 6 volts. Now take a wire and connect pin1 to VCC.
TTL inputs are best driven by pulling them down or letting them be pulled up with a obvious name, here pullup resistor. You must connect the inputs directly to ground to have them seen as a Low 0.
Where should I connect the LED on pin 2 of ? Write the truth table, get the pinout and follow the same pattern. You can proceed like this for The inputs of bipolar TTL parts will usually appear as logic High 1 when not connected.
If this gives you too much trouble mentally, 74hv08 unused inverters to switch the input and output polarities. Those parts are CMOS, so my last paragraph applies. You do need a current-lilmiting resistor Ohms or so in series with the LED, but with pin 1 tied to Vcc, the output of the inverter on pin 2 will be Low, so the LED won’t light.
Sign up using Email and Password. Post as a guest Name. You need to repeat it six times to check all gates.
It’s just logic High and Low.